有一个日志表,记录每日(date)不同类型(datatype) 数据值 格式如下
mysql> select * from userlog;
+-----+------------+----------+-----------+--------+
| uid | date | datatype | datavalue | logger |
+-----+------------+----------+-----------+--------+
| 4 | 2020-03-03 | 1 | 83 | 2 |
| 4 | 2020-04-04 | 1 | 82 | 1 |
| 5 | 2020-03-03 | 1 | 83 | 2 |
| 6 | 2020-03-03 | 1 | 70 | 3 |
| 6 | 2020-04-04 | 5 | 23 | 3 |
| 6 | 2020-04-04 | 6 | 20 | 3 |
| 6 | 2020-04-04 | 7 | 37 | 3 |
| 6 | 2020-04-04 | 10 | 38 | 3 |
+-----+------------+----------+-----------+--------+
23 rows in set (0.00 sec)
我需要列出各项数据的最新状态时,并用了 group by 和 order by , 发现sql脚本并未如我期望地展示数据
mysql> SELECT * FROM userlog
WHERE uid
= 4 GROUP BY datatype
ORDER BY date
DESC;
+-----+------------+----------+-----------+--------+
| uid | date | datatype | datavalue | logger |
+-----+------------+----------+-----------+--------+
| 4 | 2020-03-03 | 1 | 83 | 2 |
+-----+------------+----------+-----------+--------+
1 row in set (0.00 sec)
原因很好理解,处理的顺序是 先按自然顺序 group 了,才对结果 date 做 order DESC;
- 阅读剩余部分 -